Bob Dusek wrote:
...
>table second_table (
>
> this_id int,
> price money,
> ...
> ..
> trans_id int, -- my primary key association
>
>);
...
>What I need to do is to obtain the sum of the field 'price' from
>second_table for every distinct 'trans_id' (all of which can be found in
>first_table). ... Is there a quicker way to do this? Is it possible to
>use the aggregate functions and have more than one row returned?
select sum(price) from second_table group by trans_id;
--
Oliver Elphick Oliver.Elphick@lfix.co.uk
Isle of Wight http://www.lfix.co.uk/oliver
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