well if everything in a single query is that imp u may do this subselect:
select answer_id , 1.0*count(*) / (select count(*) from polls where poll_id = ?) from polls where poll_id = ?
groupby answer_id ;
and if u need to trim the trailing digits after decimal
do to_char(value , '99.99')
since u have not provided any sample data i cann't test it.
> On 04/15/03 22:40:37 +0530 mallah@trade-india.com wrote:
>
>>> I have a table being used for poll results:
>>>
>>> id
>>> poll_id
>>> question_id
>>> answer_id
>>> datestamp
>>>
>>> I what to figure out the percentage or respondants that gave each answer. This is based on
>>> occurance rather than values.
>>
>> select answer_id , 1.0*count(*) / (select count(*) from polls where poll_id = ?) from polls where poll_id =
?group by answer_id ;
>>
>> gives number of response of each answer
>>
>> total_response = select count(*) from polls where poll_id = ?
>>
>> getting %age shud be trivial.
>>
>> Dunno if i missed your question .
>
> I'm looking to do everything in a single query.
>
> And get something like:
>
> answer_id -> percentage
>
> Thanks,
>
> A.
>
> --
> Adam Sherman
> Tritus CG Inc.
> http://www.tritus.ca/
> +1 (613) 797-6819
>
>
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