Thanks :) it works as expected
Julien
On Wed, 2007-11-14 at 14:31 +0100, hubert depesz lubaczewski wrote:
> On Wed, Nov 14, 2007 at 02:39:02PM +0100, Julien Cigar wrote:
> > With the following I got a syntax error:
> > select specimen_id
> > from specimen_test_bits
> > where test_bit_id = all(1,2,3,4);
>
> where test_bit_id in (1,2,3,4)
> group by specimen_id
> having count(distinct test_bit_id) = 4;
>
> depesz
>
