Hi
I have modified the SQL query given by you and I hope the query given below will give you the correct count. SELECT
U.USER_ID, U.NAME , COUNT(*) FROM USER U , CALL C , CALLER_SESSION CS
WHERE C.CALLER_SESSION_ID = CS.CALLER_SESSION_ID AND U.USER_ID = CS.USER_ID AND CAST( CS.SESSION_DATE AS DATE ) = CAST(
'2005-04-13'AS DATE )
GROUP BY U.USER_ID
Regards,
R.Muralidharan
-----Original Message-----
From: Matt Fulford [mailto:mtfulford@yahoo.co.uk]
Sent: Wednesday, April 13, 2005 10:59 PM
To: pgsql-sql@postgresql.org
Subject: [SQL] SQL subquery (count distinct) - Any Ideas?
I'm trying to write a query to return the number of different customers
called on a single day. The database has a table called 'user', a table
called 'caller_session' which references a 'user' record, and a table called
'call' which references a 'caller_session'. This is my current attempt:
select
user.name,
sum((select count(distinct call.customer_id) from call where
call.caller_session_id=cs.caller_session_id)) as contacted
from user, caller_session cs
where cs.user_id=user.user_id
and date(cs.session_date) = date('2005-04-13')
group by user.name;
I get back a list of names and a call count (as desired), but the count is
not correct! The subqery is counting the number of different customers
called for each caller_session, and summing them based on the user.name
field. If the same customer is called in 2 different sessions, this is
being counted as 2 customers, but should be 1!
The 'contacted' count calculation has to be in a subquery as above, because
there are other subqueries after this one to calculate other data based on
the outer query (the outer query has to be as it is here). Not quite sure
where the sum, count and distinct should really go to get the required
results!
Any help greatly appreciated!
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