That's pretty nifty code. It certainly looks nicer, and looks like it would
work providing vendor_id&item_id is the pk of item_vendors (and it is). I
will let you know if it runs any faster...
Thanks
Terry Fielder
Manager Software Development and Deployment
Great Gulf Homes / Ashton Woods Homes
terry@greatgulfhomes.com
Fax: (416) 441-9085
> -----Original Message-----
> From: Matt Chatterley [mailto:zen31329@zen.co.uk]
> Sent: Monday, March 08, 2004 3:41 PM
> To: terry@ashtonwoodshomes.com
> Cc: pgsql-sql@postgresql.org
> Subject: RE: [SQL] Trying to make efficient "all vendors who
> can provide
> all items"
>
>
> Hmm. My PGSQL knowledge is rusty, so this may be slightly
> microsoftified..
>
> How about just:
>
> SELECT V.VendorID, V.VendorName, COUNT(IV.ItemID)
> FROM Vendor V
> INNER JOIN Item_Vendor IV ON IV.VendorID = V.VendorID AND
> IV.ItemID IN (1,
> 2, 3, 4, 5)
> GROUP BY V.VendorID, V.VendorName
> HAVING COUNT(IV.ItemID) = 5
>
