Alex Pilosov <alex@pilosoft.com> wrote:
> On Tue, 26 Jun 2001, Dmitry G. Mastrukov wrote:
>
> > myself some things.
> > I've marked "=" operator with HASH clause (and planner has started to
use
> > hash jons). But as I understand the right way is to create special hash
> > function (may be wrapper for hash_any(), isn't it?) and register it for
hash
> > as for btree method.
>
> No. Currently, there's no way to specify a hash function for a given
> operator, it always uses a builtin function that operates on memory
> representation of a value.
>
> There's no need (or possibility) to register a hash with btree method.
>
Strange. When I execute following query (slightly modified query from User's
Guide chapter 7.6)
SELECT am.amname AS acc_name, opc.opcname AS ops_name, opr.oprname AS ops_comp FROM pg_am am, pg_amop amop,
pg_opclass opc, pg_operator opr WHERE amop.amopid = am.oid AND amop.amopclaid = opc.oid AND
amop.amopopr= opr.oid ORDER BY ops_name, ops_comp;
I see both hash and btree amname for builtin opclasses. For example
acc_name | ops_name | ops_comp
----------+----------+----------btree | int4_ops | <btree | int4_ops | <=btree | int4_ops | =hash |
int4_ops| =btree | int4_ops | >btree | int4_ops | >=
But new type has no hash for "=". Plus I saw hash functions for builtin
types in source code. So can I achieve for created type such intergration
with Postgres as for builtin types? Or am I understanding something wrong?
regards,
Dmitry
