Re: pgbench - allow to create partitioned tables - Mailing list pgsql-hackers
From | Fabien COELHO |
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Subject | Re: pgbench - allow to create partitioned tables |
Date | |
Msg-id | alpine.DEB.2.21.1909141430550.13770@lancre Whole thread Raw |
In response to | Re: pgbench - allow to create partitioned tables (Amit Kapila <amit.kapila16@gmail.com>) |
Responses |
Re: pgbench - allow to create partitioned tables
|
List | pgsql-hackers |
Hello Amit, >>>> I'm ensuring that there is always a one line answer, whether it is >>>> partitioned or not. Maybe the count(*) should be count(something in p) to >>>> get 0 instead of 1 on non partitioned tables, though, but this is hidden >>>> in the display anyway. >>> >>> Sure, but I feel the code will be simplified. I see no reason for >>> using left join here. >> >> Without a left join, the query result is empty if there are no partitions, >> whereas there is one line with it. This fact simplifies managing the query >> result afterwards because we are always expecting 1 row in the "normal" >> case, whether partitioned or not. > > Why can't we change it as attached? I think that your version works, but I do not like much the condition for the normal case which is implicitely assumed. The solution I took has 3 clear-cut cases: 1 error against a server without partition support, detect multiple pgbench_accounts table -- argh, and then the normal expected case, whether partitioned or not. Your solution has 4 cases because of the last implicit zero-row select that relies on default, which would need some explanations. > I find using left join to always get one row as an ugly way to > manipulate the results later. Hmmm. It is really a matter of taste. I do not share your distate for left join on principle. In the case at hand, I find that getting one row in all cases pretty elegant because there is just one code for handling them all. > We shouldn't go in that direction unless we can't handle this with some > simple code. Hmmm. Left join does not strike me as over complex code. I wish my student would remember that this thing exists:-) > What is the need of using regress_pgbench_tap_1_ts in this test? I wanted to check that tablespace options work appropriately with partition tables, as I changed the create table stuff significantly, and just using "pg_default" is kind of cheating. > I think we don't need to change existing tests unless required for the > new functionality. I do agree, but there was a motivation behind the addition. > * > - 'pgbench scale 1 initialization'); > + 'pgbench scale 1 initialization with options'); > > Similar to the above, it is not clear to me why we need to change this? Because I noticed that it had the same description as the previous one, so I made the test name distinct and more precise, while I was adding options on it. > *pgbench( > - > # given the expected rate and the 2 ms tx duration, at most one is executed > '-t 10 --rate=100000 --latency-limit=1 -n -r', > 0, > > The above appears to be a spurious line change. Indeed. I think that this empty line is a typo, but I can let it as it is. > * I think we need to change the docs [1] to indicate the new step for > partitioning. See section --init-steps=init_steps > > [1] - https://www.postgresql.org/docs/devel/pgbench.html The partitioned table generation is integrated into the existing create table step, it is not a separate step because I cannot see an interest to do something in between the table creations. Patch v8 attached adds some comments around partition detection, ensures that 0 is returned for the no partition case and let the spurious empty line where it is. -- Fabien.
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