Hello Thomas,
>>> Function nbits(), which was previously discussed, has been simplified by
>>> using the function pg_popcount64().
>
> Hi Fabien, Suzuki-san,
>
> I am not smart enough to commit this
I'm in no hurry:-)
> or judge its value for benchmarking,
I think that it is valuable given that we have non uniform random
generators in pgbench.
I'm wondering about the modular_multiply manual implementation which adds
quite a few lines of non trivial code. If int128 is available on all/most
platforms, it could be removed and marked as not supported on these,
although it would create an issue with non regression tests.
> but I have a few trivial comments on the language:
>
> + It allows to mix the output of non uniform random functions so that
>
> "It allows the output of non-uniform random functions to be mixed so that"
Fixed.
> + ensures that a perfect permutation is applied: there are no collisions
> + nor holes in the output values.
>
> "neither collisions nor holes", or "no collisions or holes"
I choose the first.
> + The function errors if size is not positive.
>
> "raises an error"
Fixed.
> + * 24 bits mega primes from https://primes.utm.edu/lists/small/millions/
>
> "24 bit mega primes"
Fixed.
> +/* length of n binary representation */
> +static int
> +nbits(uint64 n)
> +{
> + /* set lower bits to 1 and count them */
> + return pg_popcount64(compute_mask(n));
> +}
>
> I suppose you could use n == 0 ? 0 : pg_leftmost_one_pos64(n) + 1, and then...
It would create a branch, that I'm trying to avoid.
> +/* return smallest mask holding n */
> +static uint64
> +compute_mask(uint64 n)
> +{
> + n |= n >> 1;
> + n |= n >> 2;
> + n |= n >> 4;
> + n |= n >> 8;
> + n |= n >> 16;
> + n |= n >> 32;
> + return n;
> +}
>
> ... here you could use 1 << nbits(n)) - 1. I have no idea if doing it
> that way around is better, it's just a thought and removes a few lines
> of bit-swizzling code.
This would create a infinite recursion as nbits currently uses
compute_mask. The 6 bitfield operation above is pretty efficient, I'd let
it at that.
Attached a v16.
--
Fabien.