Hi
suppose I have the following situation:
city date
---------+-----------------------
London | 2002-08-08 07:05:16+00
London | 2002-07-30 13:08:22+00
London | 2002-07-30 07:39:15+00
London | 2002-07-29 17:51:47+00
London | 2002-07-29 17:45:49+00
London | 2002-07-29 17:45:47+00
Paris | 2002-04-08 15:04:28+00
Paris | 2002-03-29 17:22:18+00
Paris | 2002-02-15 12:50:32+00
Paris | 2002-01-22 11:40:22+00
Paris | 2002-01-07 17:41:23+00
Paris | 2001-11-12 16:37:37+00
Paris | 2001-11-05 15:28:23+00
Paris | 2001-11-05 08:21:19+00
Oslo | 2002-07-19 15:42:20+00
Oslo | 2002-07-19 15:42:18+00
Oslo | 2002-07-18 10:03:58+00
Oslo | 2002-07-18 08:56:30+00
Oslo | 2002-07-17 17:17:27+00
Oslo | 2002-07-17 16:11:38+00
For each city I have a couple of dates in DESC order.
For each city i need to get the first record which date
comes after a given date. If the given date was for example
"2002-07-19 15:39:15+00", I would get the following
records:
London | 2002-07-29 17:45:47+00
Oslo | 2002-07-19 15:42:18+00
Is there a way to obtain this records by performing one
single query and not by making for each city something like
"SELECT city,date FROM table WHERE city='London' AND date>'2002-07-19
15:39:15+00' ORDER BY date ASC LIMIT 1;"?
Thanks.
