Tom Lane writes:
> > Actually functions do have to be schema local. It's in the spec (don't
> > have exactly where with me).
>
> (A) I don't believe that; please cite chapter and verse;
In SQL99, chapter 4 verse 23 it says
"An SQL-invoked routine is an element of an SQL-schema and is called a
schema-level routine."
> (B) even if
> SQL92 thinks that's okay, we can't do it that way because of
> backwards-compatibility issues.
I don't buy that. If all you're looking for is preserving
foo.bar <==> bar(foo)
for compatibility, then you can simply say that "bar" cannot be
schema-qualified in the left form (so it needs to live in the current or
the default schema). We currently only have one default schema, so that's
backward compatible. I think this syntax is a mistake, so I don't feel
compelled to provide more than backwards compatibility.
--
Peter Eisentraut peter_e@gmx.net
