Scadinavian characters in regular expressions - Mailing list pgsql-sql

From Søren Vainio
Subject Scadinavian characters in regular expressions
Date
Msg-id 910513A5A944D5118BE900C04F67CB5A1F82C5@MAIL
Whole thread Raw
Responses Re: Scadinavian characters in regular expressions  (Andreas Joseph Krogh <andreak@officenet.no>)
List pgsql-sql
Can someone please explain the following?
I am using a regular expression to find strings containing two words (begin with one or more characters not being spaces followed by a space followed by one or more characters not being spaces).
But when scandinavian characters are included it returns different results depending on where the character is positioned.
The first two-word example returns TRUE as expected.
The second three-word example returns FALSE as expected.
But when I let an å (&#229 &aring a-ring) traverse through the string it unexpectedly returns TRUE when the character is positioned as the second-last or last character in the two first words.
 
SELECT 'one two' ~ '^[^ ]+[ ][^ ]+$'; returns TRUE
SELECT 'one two three' ~ '^[^ ]+[ ][^ ]+$'; returns FALSE
SELECT 'åone two three' ~ '^[^ ]+[ ][^ ]+$'; returns FALSE
SELECT 'oåne two three' ~ '^[^ ]+[ ][^ ]+$'; returns FALSE
SELECT 'onåe two three' ~ '^[^ ]+[ ][^ ]+$'; returns TRUE
SELECT 'oneå two three' ~ '^[^ ]+[ ][^ ]+$'; returns TRUE
SELECT 'one åtwo three' ~ '^[^ ]+[ ][^ ]+$'; returns FALSE
SELECT 'one tåwo three' ~ '^[^ ]+[ ][^ ]+$'; returns FALSE
SELECT 'one twåo three' ~ '^[^ ]+[ ][^ ]+$'; returns TRUE
SELECT 'one twoå three' ~ '^[^ ]+[ ][^ ]+$'; returns TRUE
SELECT 'one two åthree' ~ '^[^ ]+[ ][^ ]+$'; returns FALSE
SELECT 'one two tåhree' ~ '^[^ ]+[ ][^ ]+$'; returns FALSE
SELECT 'one two thåree' ~ '^[^ ]+[ ][^ ]+$'; returns FALSE
SELECT 'one two thråee' ~ '^[^ ]+[ ][^ ]+$'; returns FALSE
SELECT 'one two threåe' ~ '^[^ ]+[ ][^ ]+$'; returns FALSE
SELECT 'one two threeå' ~ '^[^ ]+[ ][^ ]+$'; returns FALSE
 
Thank you for any response.
 
Søren Vainio, Denmark

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