This is the whole trigger
Begin
If new.pump1 = 'True'
then
Insert into p_id.devices (p_id_id, process_id, fluid_id, status,
process_graphics_id, device_description)
values (new.p_id_id, new.process_id, new.fluid_id, 'Pump #1', '11',
'Pump');
End if;
If new.pump2 = 'True'
then
Insert into p_id.devices (p_id_id, process_id, fluid_id, status,
process_graphics_id, device_description)
values (new.p_id_id, new.process_id, new.fluid_id, 'Pump #2', '11',
'Pump');
End if ;
RETURN NULL;
END;
Bob
----- Original Message -----
From: "Adrian Klaver" <adrian.klaver@gmail.com>
To: "Tom Lane" <tgl@sss.pgh.pa.us>
Cc: "Bob Pawley" <rjpawley@shaw.ca>; "Postgresql"
<pgsql-general@postgresql.org>
Sent: Friday, January 22, 2010 3:01 PM
Subject: Re: [GENERAL] Old/New
> On Friday 22 January 2010 2:05:02 pm Tom Lane wrote:
>> "Bob Pawley" <rjpawley@shaw.ca> writes:
>> > Instead I get two identical rows inserted containing the fluid_id =
>> > '3501' and 'Pump #1'.
>>
>> Seems like the only way that's possible with the INSERT .. VALUES
>> formulation is if the trigger function gets executed twice. Maybe you
>> accidentally created two instances of the trigger? psql's \d on the
>> table should list the triggers for you.
>>
>> regards, tom lane
>
> In addition to the above, is there more to the trigger function then what
> you
> have shown so far?
>
> --
> Adrian Klaver
> adrian.klaver@gmail.com
>
> --
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