Joe Conway <mail@joeconway.com> writes:
> In transformExpr the comment implies that it should be safe to reapply
> to an already transformed expression. What if we free the raw_parser
> expression list/cells/nodes and replace it with the as-transformed one?
How are you going to do the "replace" bit? The entire problem is that
you don't know where are all the down-links leading to the subexpression
you are currently working on.
The reason we could safely list_free inside transformInsertRow is that
we know all its callers have just built the passed-in list and so there
are no other pointers to it. That doesn't apply in the general case of
grammar output.
I think in the long run we probably ought to fix things so that the
grammar never outputs any multiply-linked trees; that little shortcut
has been a continuing source of grief for many reasons. I can't see
doing that for 8.2 though. My advice is to get that low-hanging fruit
in transformInsertRow and leave the other ideas for 8.3.
regards, tom lane
