Re: Examples required in || 5.10. Table Partitioning - Mailing list pgsql-docs

From Bruce Momjian
Subject Re: Examples required in || 5.10. Table Partitioning
Date
Msg-id 20200314194220.GA22336@momjian.us
Whole thread Raw
In response to Examples required in || 5.10. Table Partitioning  (PG Doc comments form <noreply@postgresql.org>)
Responses Re: Examples required in || 5.10. Table Partitioning  (Tanay Purnaye <tanay.purnaye@gmail.com>)
List pgsql-docs
On Thu, Feb  6, 2020 at 12:23:46PM +0000, PG Doc comments form wrote:
> The following documentation comment has been logged on the website:
> 
> Page: https://www.postgresql.org/docs/12/ddl-partitioning.html
> Description:
> 
> Hello ,
> 
> As I'm searching for the official documentation of Hash Partition and List
> Partition with example with more description the only information is found
> is  as below :
> 
> List Partitioning
> The table is partitioned by explicitly listing which key values appear in
> each partition.
> 
> Hash Partitioning
> The table is partitioned by specifying a modulus and a remainder for each
> partition. Each partition will hold the rows for which the hash value of the
> partition key divided by the specified modulus will produce the specified
> remainder.
> 
> But how to create and manage these above 2 partition is not explained in
> documentation properly officially.for further information related to these 2
> partition we need to search private blogs,because of lack of information
> provided in the documentation 5.10. Table Partitioning I only saw the Range
> partition example throughout the Table Partitioning .
> 
> I request you to modify the 5.10. Table Partitioning section and make it
> more informative as Table Partition is very important in PostgreSQL .

Well, there are examples in the CREATE TABLE manual page:

    https://www.postgresql.org/docs/12/sql-createtable.html

    When creating a hash partition, a modulus and remainder must be
    specified. The modulus must be a positive integer, and the remainder
    must be a non-negative integer less than the modulus. Typically, when
    initially setting up a hash-partitioned table, you should choose a
    modulus equal to the number of partitions and assign every table the
    same modulus and a different remainder (see examples, below). However,
    it is not required that every partition have the same modulus, only that
    every modulus which occurs among the partitions of a hash-partitioned
    table is a factor of the next larger modulus. This allows the number of
    partitions to be increased incrementally without needing to move all the
    data at once. For example, suppose you have a hash-partitioned table
    with 8 partitions, each of which has modulus 8, but find it necessary to
    increase the number of partitions to 16. You can detach one of the
    modulus-8 partitions, create two new modulus-16 partitions covering the
    same portion of the key space (one with a remainder equal to the
    remainder of the detached partition, and the other with a remainder
    equal to that value plus 8), and repopulate them with data. You can then
    repeat this -- perhaps at a later time -- for each modulus-8 partition
    until none remain. While this may still involve a large amount of data
    movement at each step, it is still better than having to create a whole
    new table and move all the data at once.

    CREATE TABLE orders (
        order_id     bigint not null,
        cust_id      bigint not null,
        status       text
    ) PARTITION BY HASH (order_id);

    CREATE TABLE orders_p1 PARTITION OF orders
        FOR VALUES WITH (MODULUS 4, REMAINDER 0);
    CREATE TABLE orders_p2 PARTITION OF orders
        FOR VALUES WITH (MODULUS 4, REMAINDER 1);
    CREATE TABLE orders_p3 PARTITION OF orders
        FOR VALUES WITH (MODULUS 4, REMAINDER 2);
    CREATE TABLE orders_p4 PARTITION OF orders
        FOR VALUES WITH (MODULUS 4, REMAINDER 3);


    CREATE TABLE cities (
        city_id      bigserial not null,
        name         text not null,
        population   bigint
    ) PARTITION BY LIST (left(lower(name), 1));

    CREATE TABLE cities_ab
        PARTITION OF cities (
        CONSTRAINT city_id_nonzero CHECK (city_id != 0)
    ) FOR VALUES IN ('a', 'b');

Is that sufficient?

-- 
  Bruce Momjian  <bruce@momjian.us>        https://momjian.us
  EnterpriseDB                             https://enterprisedb.com

+ As you are, so once was I.  As I am, so you will be. +
+                      Ancient Roman grave inscription +



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