On 2014-03-31 12:16:53 -0700, David Johnston wrote:
> Leonardo M. Ramé-2 wrote
> > select lag.id, lag.idtask, lag.code, lag.lg from (select idtask, code, id,
> > lag(code, -1) over () as lg from tasks_test) as lag
>
> First you want to include an ORDER BY in the OVER(...) clause, and probably
> a PARTITION BY as well.
>
> Then you move that to a sub-query (for example):
>
> SELECT *
> FROM tbl
> WHERE tbl.idtask IN (
> SELECT lag.idtask FROM ( lag_query_here ) lag WHERE lag.code = 'T' and
> lag.lg = 'S'
> );
>
> David J.
>
Great!, that's what I needed, thank you.
--
Leonardo M. Ramé
Medical IT - Griensu S.A.
Av. Colón 636 - Piso 8 Of. A
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