Scott Marlowe <scott.marlowe@gmail.com> schrieb:
> >> You can use a subquery like my example:
> >>
> >> test=*# select i, comma(t) from (select distinct i,t from foo) bar group by i;
> >> i | comma
> >> ---+---------
> >> 1 | a, b, c
> >> (1 row)
> >>
> >> Time: 0.554 ms
> >> test=*# select i, comma(t) from (select distinct i,t from foo order by t desc) bar group by i;
> >
> > Thanks Andreas, that would be good solution.
> >
> > (still curious about the "must be used in an aggregate function" error
> > though... because I do use it in an aggregate)
>
> You can order by the same thing you selected:
>
> select sum(i) from ... group by j order by sum(i)
> OR
> select sum(i) from ... group by j order by 1 -- 1 stands for the
> first select list item...
Not in this case:
test=# select i, comma(distinct t ) from foo group by i order by
comma(t) desc;i | comma
---+---------1 | a, b, c
(1 row)
doesn't work as desired.
Andreas
--
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unintentional side effect. (Linus Torvalds)
"If I was god, I would recompile penguin with --enable-fly." (unknown)
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