On Wed, Nov 22, 2006 at 08:20:40AM -0500, Greg Mitchell wrote:
> Below are the operator definitions for one type. The other types are
> exactly the same, just different argument types and procedures.
Looks good, what about the operator class definition?
Have a nice day,
--
Martijn van Oosterhout <kleptog@svana.org> http://svana.org/kleptog/
> From each according to his ability. To each according to his ability to litigate.
