Mr. Aaron. I am sorry, your solution didn't match in my case.
Example for your solution :
A = 1
B = 1
C = 1
D = 1
E = 1
F = 1
G = 4
G have 4 candy. Its too much for G.
In my case, the solution is :
A = 1
B = 1
C = 1
D = 1
E = 2
F = 2
G = 2
The extra candy is given to three child.
Do you have the other solution? I need function in postgresql for my case.
Because my loop is too slow.
Btw thanks for your solution.
Aaron Bono <postgresql@aranya.com> wrote:
On 7/25/06, Otniel Michael <otmic_ie@yahoo.com> wrote:Dear All,
I have a problem with this case :
I have 10 candy for 7 child (A, B, C, D, E, F, G).
Table X :
code value
------- --------
A 0
B 0
C 0
D 0
E 0
F 0
G 0
And I want divide it with this algorithm :
A = 10 / 7 = 1
B = (10-1) / (7-1) = 9 / 6 = 1
C = (10-2) / (7-2) = 8 / 5 = 1
D = (10-3) / (7-3) = 7 / 4 = 1
E = (10-4) / (7-4) = 6 / 3 = 2
F = (10-6) / (7-5) = 4 / 2 = 2
G = (10-8) / (7-6) = 2 / 1 = 2
In my first solution i use loop - for each record in my function.
But it is too slow in a lot of data.
Did postgresql have a function for my case?
No loop necessary. This is a simple math problem:
dividedamount := candy / childcount;
extra = candy % childcount;
So the first (childcount - extra) get (dividedamount) pieces of candy and the last (extra) get (dividedamount + 1) pieces of candy.
==================================================================
Aaron Bono
Aranya Software Technologies, Inc.
http://www.aranya.com
==================================================================
--
"He who is quick to become angry will commit folly, and a crafty man is hated"
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