RE: SQL help... - Mailing list pgsql-general

From Alex Hochberger
Subject RE: SQL help...
Date
Msg-id 1F3774AB3688D4118B1300508BD9641528A7E1@CHINA
Whole thread Raw
In response to SQL help...  (Alex Hochberger <alex@feratech.com>)
Responses RE: SQL help...
RE: SQL help...
List pgsql-general
Users:
----------------------
CREATE TABLE "users" (
   "user_id" int8 DEFAULT nextval('user_id_seq'::text) NOT NULL,
   "group_id" int4 NOT NULL,
   "user_agent" varchar(200) NOT NULL,
   "ip_address" varchar(20) NOT NULL,
   CONSTRAINT "users_pkey" PRIMARY KEY ("user_id")
);
CREATE  UNIQUE INDEX "user_id_users_ukey" ON "users" ("user_id");
CREATE  INDEX "users_group_id_key" ON "users" ("group_id");
CREATE  INDEX "users_ip_address_key" ON "users" ("ip_address");
CREATE  INDEX "users_user_agent_key" ON "users" ("user_agent");

Questions:
----------------------
CREATE TABLE "questions" (
   "question_id" int8 DEFAULT nextval('question_id_seq'::text) NOT NULL,
   "survey_id" int4 NOT NULL,
   "question" text NOT NULL,
   CONSTRAINT "questions_pkey" PRIMARY KEY ("question_id")
);
CREATE  INDEX "questions_question_key" ON "questions" ("question");
CREATE  INDEX "questions_survey_id_key" ON "questions" ("survey_id");


User Answers:
----------------------
CREATE TABLE "user_answers" (
   "ua_id" int8 DEFAULT nextval('ua_id_seq'::text) NOT NULL,
   "user_id" int8 NOT NULL,
   "question_id" int8 NOT NULL,
   "qa_id" int8 NOT NULL,
   CONSTRAINT "user_answers_pkey" PRIMARY KEY ("ua_id")
);
CREATE  INDEX "user_answers_qa_id_key" ON "user_answers" ("qa_id");
CREATE  INDEX "user_answers_question_id_key" ON "user_answers"
("question_id");
CREATE  INDEX "user_answers_user_id_key" ON "user_answers" ("user_id");


All these questions will be for survey 1...

Alex

> -----Original Message-----
> From: Ryan Mahoney [mailto:ryan@paymentalliance.net]
> Sent: Tuesday, May 15, 2001 7:22 PM
> To: Alex Hochberger; 'pgsql-general@postgresql.org'
> Subject: Re: [GENERAL] SQL help...
>
>
> Please post the sql statement that creates these tables.
>
> -r
>
> At 12:15 AM 5/16/01 -0400, Alex Hochberger wrote:
>
> >To any SQL wizards out there,
> >
> >I have finally exhausted my SQL knowledge.
> >
> >I have 3 tables that I need to do a fancy join on...
> >
> >1 stores the users
> >1 stores the questions
> >1 stores the user's answers to the questions (based on
> foreign keys to the
> >answers table)
> >
> >I would like to create a result with the following columns:
> >some fields from the users, each of the questions
> >
> >in each row should be the results from the users, and their
> user answers
> >
> >Here is the tricky thing, people may have not answered each
> question, so I
> >would like to either leave that blank or put in a 0...
> >
> >With an ugly hack, I get the results where they answered
> everything, but not
> >the partial answers.
> >
> >Please cc: me on the reply, because I get this as a digest.
> >
> >Thanks,
> >Alex
> >
> >---------------------------(end of
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