Re: column totals - Mailing list pgsql-performance

From Ragnar
Subject Re: column totals
Date
Msg-id 1148660617.8566.51.camel@localhost.localdomain
Whole thread Raw
In response to column totals  (James Neethling <james@silversphere.co.za>)
List pgsql-performance
On fös, 2006-05-26 at 11:56 +0200, James Neethling wrote:

> SELECT branch_id, prod_cat_id, sum(prod_profit) as prod_cat_profit
>     FROM () as b1
> WHERE x = y
> GROUP BY branch, prod_cat_id
>
>
> Now, I also need the branch total, effectively,
> SELECT branch_id, sum(prod_profit) as branch_total
>     FROM () as b1
> WHERE x = y
> GROUP BY branch_id.
>
>
> Since the actual queries for generating prod_profit are non-trivial, how
> do I combine them to get the following select list?

one simple way using temp table and 2 steps:

CREATE TEMP TABLE foo AS
  SELECT branch_id,
         prod_cat_id,
         sum(prod_profit) as prod_cat_profit
  FROM () as b1
  WHERE x = y
  GROUP BY branch, prod_cat_id;

SELECT branch_id,
       prod_cat_id,
       prod_cat_profit,
       branch_total
FROM foo as foo1
     JOIN
       (SELECT branch_id,
               sum(prod_cat_profit) as branch_total
        FROM foo
        GROUP BY branch_id
       ) as foo2 USING branch_id;


(untested)

gnari



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