Re: Join question - Mailing list pgsql-sql

From Edward W. Rouse
Subject Re: Join question
Date
Msg-id 064001c90200$80eef7d0$82cce770$@com
Whole thread Raw
In response to Re: Join question  ("Daniel Hernandez" <breydan@excite.com>)
Responses Re: Join question
List pgsql-sql

I have tried left, right outer and inner.

 

Edward W. Rouse

 

From: Daniel Hernandez [mailto:breydan@excite.com]
Sent: Monday, August 18, 2008 12:30 PM
To: pgsql-sql@postgresql.org; erouse@comsquared.com
Subject: Re: [SQL] Join question

 

have you tried a right Join?


Daniel Hernndez.
San Diego, CA.
"The more you learn, the more you earn".
Fax: (808) 442-0427


-----Original Message-----
From: "Edward W. Rouse" [erouse@comsquared.com]
Date: 08/15/2008 09:48 AM
To: pgsql-sql@postgresql.org
Subject: Re: [SQL] Join question

I have 2 tables, both have a user column. I am currently using a left join from table a to table b because I need to show all users from table a even those not having an entry in table b. The problem is I also have to include items from table b with that have a null user. There are some other criteria as well that are simple where clause filters. So as an example:

 

Table a:

Org|user

A    | emp1

B    | emp1

B    | emp2

B    | emp3

C    | emp2

 

Table b:

Org|user|color

A   |emp1|red

A   |emp1|blue

A   |null|pink

A   |null|orange

B   |emp1|red

B   |emp3|red

B   |null|silver

C   |emp2|avacado

 

If I:

 

select org, user, count(total)

from a left join b

on (a.org = b.org and a.user = b.user)

where a.org = ‘A’

group by a.org, a.user

order by a.org, a.user

 

I get:

 

Org|user|count

A    |emp1|2

A    |emp2|0

A    |emp3|0

 

But what I need is:

 

A    |emp1|2

A    |emp2|0

A    |emp3|0

A    |null|2

 

Thanks,

Edward W. Rouse

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