Re: 7.3 "group by" issue - Mailing list pgsql-sql

From Chad Thompson
Subject Re: 7.3 "group by" issue
Date
Msg-id 053901c2d9eb$0cd85000$32021aac@chad
Whole thread Raw
In response to Re: 7.3 "group by" issue  ("Dan Langille" <dan@langille.org>)
Responses Re: 7.3 "group by" issue  (Josh Berkus <josh@agliodbs.com>)
List pgsql-sql


> On 21 Feb 2003 at 13:30, Chad Thompson wrote:
>
> > The same applies to group by... Sorry for the confusion.
> >
> > If the column is not in the select section of the statement, it cant
group
> > by it.
> > Try this.
> >
> > SELECT element_id as wle_element_id, COUNT(watch_list_id)
> >    FROM watch_list JOIN watch_list_element
> >      ON watch_list.id      = watch_list_element.watch_list_id
> > WHERE
> >    watch_list.user_id = 1
> >   GROUP BY wle_element_id
>
> Yes, that works.  But so do these.
>
> SELECT watch_list_element.element_id as wle_element_id,
> COUNT(watch_list_id)
>    FROM watch_list JOIN watch_list_element
>      ON watch_list.id      = watch_list_element.watch_list_id
> WHERE
>    watch_list.user_id = 1
>   GROUP BY watch_list_element.element_id
>
>
> SELECT element_id as wle_element_id, COUNT(watch_list_id)
>    FROM watch_list JOIN watch_list_element
>      ON watch_list.id      = watch_list_element.watch_list_id
> WHERE
>    watch_list.user_id = 1
>   GROUP BY element_id
>
> The original situation which did not work is:
>
> SELECT watch_list_element.element_id as wle_element_id,
> COUNT(watch_list_id)
>    FROM watch_list JOIN watch_list_element
>      ON watch_list.id      = watch_list_element.watch_list_id
> WHERE
>    watch_list.user_id = 1
>   GROUP BY element_id
>
> My question: why should it not work?  It's referring to the same
> column as the previous two examples which do work.
> --

I see the distinction you are making.

Maybe Tom or Josh could throw out a better answer, but I think that youve
called it one thing in your select and tried to group by it using a
syntaticly different name.

Any one have any other ideas?

Chad



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