An: pgsql-sql@postgresql.org
Betreff: Re: [SQL] returning an array as a list fo single-column rows?
The following will return the elements of an array each in its
Own row. Using both array_lower() and array_upper() the number of array
Elements and their internal index may vary from record to record. Or may
even be absent.
Within the record the array nstat[],nwert[],nwho[] must correspond.
Joining the table with
generate_series(array_lower(nWert,1),array_upper(nWert,1)) as indx
returns the contained array elements.
Considering the following table with array.....
Create table werte
(id : integer, ...... ......nstat : character(1)[],nwert : double precision[],nwho : character varying(9)[]
);
select
w.id,ii.indx,
w.nStat[ii.indx],w.nWert[ii.indx],w.nWho[ii.indx]
from werte w
join
(
select id,generate_series(array_lower(nWert,1),array_upper(nWert,1)) as indxfrom werte
) ii on ii.id=w.id
;
Let me know what you think about this approach?
My best regards,
Stefan Becker
