"Albrecht Berger" <berger1517@gmx.ch> writes:
[...]
> The Statement
> SELECT * FROM XYZ WHERE name LIKE '%Müller%'
> doesn't any of a matching row.
It does work for me:
regression=# select 'Müller' LIKE '%Müller%';?column?
----------t
(1 row)
postgres version?, database encoding?, plataform?
Regards,
Manuel.