Re: Who knows this SELECT in PostgreSQL - Mailing list pgsql-admin

Michael Monnerie написа:
> Dear gurus, I'm sure someone knows immediately how to translate this
> mysql to postgresql:
>
> SELECT GROUP_CONCAT(dbmail_messageblks.messageblk
> ORDER BY dbmail_messageblks.is_header DESC SEPARATOR '')
> FROM dbmail_messages
> JOIN dbmail_messageblks ON
> (dbmail_messages.physmessage_id=dbmail_messageblks.physmessage_id)
> WHERE dbmail_messages.message_idnr='${MSG_UID}'
> GROUP BY dbmail_messages.message_idnr"
>
> It should simply return the whole message which can be truncated to
> pieces into dbmail_messageblks and return it as a single entity. I found
> this for mysql and would like to rewrite the shell script to postgresql,
> but am stuck at this select.
>
> mfg zmi


CREATE AGGREGATE public.array_agg(ANYELEMENT) (
    SFUNC = ARRAY_APPEND,
    STYPE = ANYARRAY,
    INITCOND = '{}'
);



SELECT
    ARRAY_TO_STRING(public.ARRAY_AGG(b.messageblk),'') AS the_message
FROM
    dbmail_messages AS m
JOIN
    dbmail_messageblks AS b
ON
    (m.physmessage_id = b.physmessage_id)
WHERE
    m.message_idnr = '${MSG_UID}'
GROUP BY
    m.message_idnr;






If you can wait for or want to test version 8.4 (which is in Beta
right now and would be released relatively soon) you can skip the
creation of the aggregate.


--
Milen A. Radev