Hello
SELECT age(CURRENT_DATE, date '730715');
age
--------------------------
30 years 7 days 23:00:00
(1 row)
bye
ps
On 22 Jul 2003, Ben wrote:
> It must be late, because I cannot seem to figure this out. I've got a
> field which has a user's birthday - I want to figure out how old they
> are in terms of years.
>
> If I just do something like:
>
> select current_date - user.bday;
>
> I get their age in days, which doesn't let me take leap years into
> account. Is there a simple magic date_diff function that I'm missing? Or
> lacking that some other way to get postgres to do the date calculations?
>
>
> ---------------------------(end of broadcast)---------------------------
> TIP 9: the planner will ignore your desire to choose an index scan if your
> joining column's datatypes do not match
>
