I think the correct way is
SELECT equipo_attr[1] AS year, equip_attr[2] AS make
FROM vehicle_tb;
On Mon, 12 Jun 2000, Bernie Huang wrote:
> Hi, I have a following query:
>
> "select equip_attr[1], equip_attr[2]
> as year, make
> from vehicle_tb;"
>
> which gives me the following error:
>
> "ERROR: Attribute 'make' not found"
>
> Is there something wrong with my "as" usage? Thanks
>
>
> - Bernie
>
