Re: find and replace the string within a column - Mailing list pgsql-sql

From Jayadevan M
Subject Re: find and replace the string within a column
Date
Msg-id OFF34DA862.E1543DC5-ON652577A8.00344354-652577A8.003484A7@ibsplc.com
Whole thread Raw
In response to find and replace the string within a column  (Nicholas I <nicholas.domnic.i@gmail.com>)
List pgsql-sql
Hello,
> the below one help's me to find the data within the two brackets.
> 
> SELECT name,(REGEXP_MATCHES(name, E'\\(.+?\\)'))[1] from person;
> regexp_matches
> ------------------------------------
> (S/o Sebastin )
> -------------------------------------
> 
Trying to work with your code - 
update table set name = 
substr( name,1,strpos(name, (REGEXP_MATCHES(name, E'\\(.+?\\)')) )-1 ) ||
substr( name,strpos(name, (REGEXP_MATCHES(name, E'\\(.+?\\)')) ) + 1 
,char_length(name))

I am trying to find what is there before the pattern and after the pattern 
and concatenating them . Please see documentation for proper use of 
substr,strpos,cahr_length etc. 

Regards,
Jayadevan





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