Re: SQL syntax rowcount value as an extra column in the result set - Mailing list pgsql-sql

From Jayadevan M
Subject Re: SQL syntax rowcount value as an extra column in the result set
Date
Msg-id OF3566EE01.958C8348-ON652576F2.002579A1-652576F2.002608F3@LocalDomain
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In response to Re: SQL syntax rowcount value as an extra column in the result set  ("A. Kretschmer" <andreas.kretschmer@schollglas.com>)
Responses Re: SQL syntax rowcount value as an extra column in the result set
List pgsql-sql
<tt><font size="2">Hi,</font></tt><br /><tt><font size="2">>It works, but you should use a recent version:<br /><br
/>>test=*#select count(1) over (), i from foo;<br />> count | i<br />>-------+----<br />>     8 |  1<br
/>>    8 |  2<br />>     8 |  3<br />>     8 |  6<br />>     8 |  7<br />>     8 |  9<br />>     8 |
13<br/>>     8 | 14<br />>(8 rows)<br /><br />> test=*# select version();<br />>                          
                    version<br />>
--------------------------------------------------------------------------------------------------------<br/>>
 PostgreSQL8.4.2 on x86_64-pc-linux-gnu, compiled by GCC gcc-4.3.real<br />> (Debian 4.3.2-1.1) 4.3.2, 64-bit<br
/>>(1 row)<br /></font></tt><br /><font face="sans-serif" size="2">Thank you for setting that right. Apologies for
notchecking version.</font><br /><font face="sans-serif" size="2">Is this approach better compared to </font><br
/><fontface="sans-serif" size="2">postgres=# select * from (select count(*) from people ) p, (select firstname from
people)p2;</font><br/><font face="sans-serif" size="2"> count | firstname</font><br /><font face="sans-serif"
size="2">-------+-----------</font><br/><font face="sans-serif" size="2">     5 | Mary</font><br /><font
face="sans-serif"size="2">     5 | Mary</font><br /><font face="sans-serif" size="2">     5 | John</font><br /><font
face="sans-serif"size="2">     5 | John</font><br /><font face="sans-serif" size="2">     5 | Jacob</font><br /><font
face="sans-serif"size="2">(5 rows)</font><br /><font face="sans-serif" size="2">This gives me</font><br /><font
face="sans-serif"size="2">postgres=# explain  select * from (select count(*) from people )as p, (select firstname from
people)p2;</font><br/><font face="sans-serif" size="2">                             QUERY PLAN</font><br /><font
face="sans-serif"size="2">---------------------------------------------------------------------</font><br /><font
face="sans-serif"size="2"> Nested Loop  (cost=14.00..30.42 rows=320 width=226)</font><br /><font face="sans-serif"
size="2">  ->  Aggregate  (cost=14.00..14.01 rows=1 width=0)</font><br /><font face="sans-serif" size="2">       
 -> Seq Scan on people  (cost=0.00..13.20 rows=320 width=0)</font><br /><font face="sans-serif" size="2">   ->
 SeqScan on people  (cost=0.00..13.20 rows=320 width=218)</font><br /><br /><font face="sans-serif" size="2">Since I
don'thave 8.4, I am not in a position to do explain on that version. My guess - over () will be better. My query does
sequentialscans/nested loop...(if there are no indexes)</font><br /><br /><font face="sans-serif"
size="2">Regards,</font><br/><font face="sans-serif" size="2">Regards,</font><br /><font face="Trebuchet MS"
size="2">Jayadevan</font><fontface="sans-serif"></font> <img src="http://www.ibsplc.com/images/email_footer_final.gif"
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