Re: Summing activity intervals without any obvious column to group by - Mailing list pgsql-general
From | David Johnston |
---|---|
Subject | Re: Summing activity intervals without any obvious column to group by |
Date | |
Msg-id | E913C6BA-D8AC-4361-921D-09ED88AC1765@yahoo.com Whole thread Raw |
In response to | Re: Summing activity intervals without any obvious column to group by (Carey Tilden <carey.tilden@gmail.com>) |
Responses |
Re: Summing activity intervals without any obvious column
to group by
|
List | pgsql-general |
On Mon, Aug 13, 2012 at 6:01 PM, David Johnston <polobo@yahoo.com> wrote:First artificially generate row (pair) identifiers by integer dividing the ordered row number by 2.On Aug 13, 2012, at 20:28, Carey Tilden <carey.tilden@gmail.com> wrote:
> Apologies for the awkward title. I haven't quite thought of the right way to describe my problem, which may be why I've had a hard time figuring out how to solve it. I have a list of program start/stop times, and I want to know how long each run takes to complete. The thing that's really tripping me up is there are gaps in the sequence. I've figured out how to collapse the results down to a single row per attempt, but I can't quite figure out how to further collapse down each full run to its own row. It'd be easy if I had a session_id or something to group on, but I don't. All I have are the start/stop times.
>
> Here's some sample data. Hopefully this clarifies what I'm talking about:
>
> drop table if exists program_runs;
>
> create temporary table program_runs (
> id serial,
> time_stamp timestamptz,
> action text
> );
>
> insert into program_runs (time_stamp, action) values
> ('2012-01-01 10:00:00 PST', 'started'), ('2012-01-01 10:10:00 PST', 'stopped early'),
> ('2012-01-01 10:20:00 PST', 'started'), ('2012-01-01 10:30:00 PST', 'stopped early'),
> ('2012-01-01 10:40:00 PST', 'started'), ('2012-01-01 10:47:00 PST', 'completed'),
> ('2012-01-01 10:50:00 PST', 'started'), ('2012-01-01 11:00:00 PST', 'stopped early'),
> ('2012-01-01 11:10:00 PST', 'started'), ('2012-01-01 11:13:00 PST', 'completed'),
> ('2012-01-01 11:20:00 PST', 'started'), ('2012-01-01 11:30:00 PST', 'stopped early'),
> ('2012-01-01 11:40:00 PST', 'started'), ('2012-01-01 11:50:00 PST', 'stopped early'),
> ('2012-01-01 12:00:00 PST', 'started'), ('2012-01-01 12:10:00 PST', 'stopped early'),
> ('2012-01-01 12:20:00 PST', 'started'), ('2012-01-01 12:29:00 PST', 'completed');
>
> select
> this_time_stamp as starting_time_stamp,
> next_time_stamp - this_time_stamp as time_elapsed,
> next_action as closing_action
> from (
> select
> time_stamp as this_time_stamp, lead(time_stamp) over (order by id) as next_time_stamp,
> action as this_action, lead(action) over (order by id) as next_action,
> id as this_id, lead(id) over (order by id) as next_id
> from program_runs
> ) q
> where this_action = 'started';
>
> Note that each run has a pair of entries in the table. The first is always "started", but the second may be either "stopped early" or "completed". The final results I'd like to see are:
>
> starting_time_stamp | total_time_elapsed
> ------------------------+--------------------
> 2012-01-01 10:00:00-08 | 00:27:00
> 2012-01-01 10:50:00-08 | 00:13:00
> 2012-01-01 11:20:00-08 | 00:39:00
>
> Hope that's enough detail. Any ideas or suggestions gladly accepted!
>
> Regards,
> Carey
Using window or sub-queries identify the bookends for each group (i.e., the identifier for each completed and the prior completed). Give these groups artificial session identifiers/row numbers.
Assign the artificial session id to each transaction row by using the bookends.
This is the part where I draw a blank. How would I do that? Seems like it should be easy with window functions, but I just can't think of the way to do it.
With detail as ()
, bookmarks as ()
Select detail.id, bookmarks.id, ...
From detail
Join bookmarks on ( detail.id between bookmarks.startid and bookmarks.endid )
Bookmarks as (
Select row_number() over () as id,
detail.id, coalesce(min(detail.id) over (rows 1 preceeding),0) --coalesce for the first row
From detail where 'completed'
)
Probably need to play with row ordering but this should get you started.
Now you have identifiers with which to group.
This makes a number of assumptions regarding the form of the input data. It will solve for your example data but it may not generalize. In particular it assumes non-overlapping sessions.
The assumptions hold fairly well. Sessions do not overlap, thankfully. There are different program runs to untangle, but that's simple enough (order by program_name, time_stamp).
Thanks for the suggestions so far!
Carey
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