Re: Joining time fields? - Mailing list pgsql-novice

----- Original Message -----

From: Bryan Lee Nuse

To: James David Smith

Cc: pgsql-novice@postgresql.org ; Oliveiros d'Azevedo Cristina

Sent: Thursday, July 26, 2012 5:43 PM

Subject: Re: [NOVICE] Joining time fields?

Hello James,

Here's an alternative query that I believe gets what you're asking for.  It is less clever and succinct than the one Oliveiros suggested, but may be easier to scrutinize if you are carrying a lot of additional columns through to the resulting table (you don't need to GROUP BY a bunch of columns, as you did in the query you posted).  Also, I'd suggest saving any WHERE clause for the outer query (no matter what your final code looks like), as that will help in trouble-shooting.  Like Oliveiros's query, this one rests upon a cross join, and will therefore be slow if your tables are huge.

Here's a self-contained test:

CREATE TABLE table_one (

 date_time   TIMESTAMP,

 letter   char(1)

);

CREATE TABLE table_two (

 date_time   TIMESTAMP,

 letter   char(1)

);

INSERT INTO table_one

 VALUES ('2012-06-23 11:43:26', 'A'),

  ('2010-05-16 06:45:20', 'B'),

  ('2000-01-04 15:57:01', 'C'),

  ('1993-10-06 04:36:09', 'D'); 

INSERT INTO table_two

 VALUES ('2000-06-23 11:43:26', 'W'),

  ('1994-05-16 06:45:20', 'X'),

  ('2008-01-04 15:57:01', 'Y'),

  ('1994-05-16 06:45:20', 'Z'); -- duplicate value 

The query.  Two WITH queries, the first to perform the cross join, the second to aggregate the crossed table according to the minimum time interval.  These two queries are then JOINed in the main query:

WITH 

crossed AS (

  SELECT 

    A.date_time AS dt_a,

    A.letter AS let_a,

    B.date_time AS dt_b,

    B.letter AS let_b,

    @(extract(EPOCH FROM A.date_time - B.date_time)) AS interval

    FROM

    table_one A, table_two B

    ),

grouped AS (

  SELECT dt_a, min(interval) AS interval

    FROM crossed

    GROUP BY dt_a

    )

SELECT C.*

  FROM 

  grouped G

  LEFT JOIN

    crossed C

    USING (dt_a, interval)

  ORDER BY dt_a;

Here's the output (recovers the duplicate rows in table_two, as you specified) :

        dt_a         |        dt_b         | interval  

---------------------+---------------------+-----------

 1993-10-06 04:36:09 | 1994-05-16 06:45:20 |  19188551

 1993-10-06 04:36:09 | 1994-05-16 06:45:20 |  19188551

 2000-01-04 15:57:01 | 2000-06-23 11:43:26 |  14759185

 2010-05-16 06:45:20 | 2008-01-04 15:57:01 |  74530099

 2012-06-23 11:43:26 | 2008-01-04 15:57:01 | 140989585

(5 rows)

Hope that is helpful...

Bryan