On Thu, Sep 20, 2012 at 1:55 AM, Haifeng Liu
<liuhaifeng@live.com> wrote:
I want to write a hash function which acts as String.hashCode() in java: hash = hash * 31 + s.charAt(i)... but I got integer out of range error. How can I avoid this? I saw java do not care overflow of int, it just make the result negative.
Use the bitwise AND operator to mask the hash value with 0x3FFFFFF before each iteration:
hash = (hash & 67108863) * 31 + s.charAt(i);
Craig
