On 28 October 2011 09:02, Mohamed Hashim <nmdhashim@gmail.com> wrote:
> EXPLAIN select * from stk_source ;
> QUERY
> PLAN
> -------------------------------------------------------------------------------------
> Result (cost=0.00..6575755.39 rows=163132513 width=42)
> -> Append (cost=0.00..6575755.39 rows=163132513 width=42)
> -> Seq Scan on stk_source (cost=0.00..42.40 rows=1080 width=45)
> -> Seq Scan on stk_source (cost=0.00..20928.37 rows=519179
> width=42)
> -> Seq Scan on stk_source (cost=0.00..85125.82 rows=2111794
> width=42)
> -> Seq Scan on stk_source (cost=0.00..6469658.80 rows=160500460
> width=42)
That plan gives you the best possible performance given your query.
Your example probably doesn't fit the problem you're investigating.
--
If you can't see the forest for the trees,
Cut the trees and you'll see there is no forest.
