Re: pg_amcheck contrib application - Mailing list pgsql-hackers
From | Robert Haas |
---|---|
Subject | Re: pg_amcheck contrib application |
Date | |
Msg-id | CA+TgmobmYWofcNX0iSrjyipp2K=jpPFZZMhZX_rnXJ2TnUemZQ@mail.gmail.com Whole thread Raw |
In response to | Re: pg_amcheck contrib application (Mark Dilger <mark.dilger@enterprisedb.com>) |
Responses |
Re: pg_amcheck contrib application
Re: pg_amcheck contrib application |
List | pgsql-hackers |
On Fri, Apr 30, 2021 at 2:31 PM Mark Dilger <mark.dilger@enterprisedb.com> wrote: > Just to be clear, I did not use your patch v1 as the starting point. I thought that might be the case, but I was trying to understand what you didn't like about my version, and comparing them seemed like a way to figure that out. > I took the code as committed to master as the starting point, used your corruption report verbiage changes and at leastsome of your variable naming choices, but did not use the rest, in large part because it didn't work. It caused corruptionmessages to be reported against tables that have no corruption. For that matter, your v2 patch doesn't work either,and in the same way. To wit: > > heap table "postgres"."pg_catalog"."pg_rewrite", block 6, offset 4, attribute 7: > toast value 13461 chunk 0 has size 1995, but expected size 1996 > > I think there is something wrong with the way you are trying to calculate and use extsize, because I'm not corrupting pg_catalog.pg_rewrite. You can get these same results by applying your patch to master, building, and running 'make check'from src/bin/pg_amcheck/ Argh, OK, I didn't realize. Should be fixed in this version. > > 4. You don't return if chunk_seq > last_chunk_seq. That seems wrong, > > because we cannot compute a sensible expected size in that case. I > > think your code will subtract a larger value from a smaller one and, > > this being unsigned arithmetic, say that the expected chunk size is > > something gigantic. > > Your conclusion is probably right, but I think your analysis is based on a misreading of what "last_chunk_seq" means. It's not the last one seen, but the last one expected. (Should we rename the variable to avoid confusion?) It won't computea gigantic size. Rather, it will expect *every* chunk with chunk_seq >= last_chunk_seq to have whatever size is appropriatefor the last chunk. I realize it's the last one expected. That's the point: we don't have any expectation for the sizes of chunks higher than the last one we expected to see. If the value is 2000 bytes and the chunk size is 1996 bytes, we expect chunk 0 to be 1996 bytes and chunk 1 to be 4 bytes. If not, we can complain. But it makes no sense to complain about chunk 2 being of a size we don't expect. We don't expect it to exist in the first place, so we have no notion of what size it ought to be. > If we have seen any chunks, the variable is holding the expected next chunk seq, which is one greater than the last chunkseq we saw. > > If we expect chunks 0..3 and see chunk 0 but not chunk 1, it will complain ..."expected to end at chunk 4, but ended atchunk 1". This is clearly by design and not merely a bug, though I tend to agree with you that this is a strange wordingchoice. I can't remember exactly when and how we decided to word the message this way, but it has annoyed me fora while, and I assumed it was something you suggested a while back, because I don't recall doing it. Either way, sinceyou seem to also be bothered by this, I agree we should change it. Can you review this version? -- Robert Haas EDB: http://www.enterprisedb.com
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