I’m looking for a way to find first free time in reservations table.
Reservation table contains reservations start dates, start hours and durations.
Start hour is by half hour increments in working hours 8:00 .. 18:00 in work days.
Duration is also by half hour increments in day.
CREATE TABLE reservation (
id serial primary key,
startdate date not null, -- start date
starthour numeric(4,1) not null , -- start hour 8 8.5 9 9.5 .. 16.5 17 17.5
duration Numeric(3,1) not null -- duration by hours 0.5 1 1.5 .. 9 9.5 10
);
table structure can changed if required.
How to find first free half hour in table which is not reserved ?
E.q if table contains
startdate starthour duration
14 9 1 -- ends at 9:59
14 10 1.5 -- ends at 11:29, e.q there is 30 minute gap before next
14 12 2
14 16 2
result should be:
starthour duration
11.5 0.5
Probably PostgreSql 9.2 window function should used to find
first row whose starthour is greater than previous row starthour + duration
How to write select statement which returns this information ?
Andrus.
I posted this also in
