Try this:
select user_id, project_id, date_trunc, sum(sum) FROM (select user_id,
project_id, date_trunc('day', ts), SUM(duration) FROM (select user_id,
project_id, a.ts, ((SELECT MIN(b.ts) FROM log b WHERE b.ts>a.ts AND
(date_trunc('day',a.ts)=date_trunc('day',b.ts)))-a.ts) AS duration
from log a order by user_id, project_id, ts) AS foo group by user_id,
project_id, ts) AS day_set group by user_id, project_id, date_trunc
order by user_id, project_id, date_trunc;
-Kevin Crain
On Thu, Jun 9, 2011 at 6:43 AM, Andreas <maps.on@gmx.net> wrote:
> hi,
> I have a log-table that stores events of users and projects like this
> ( user_id integer, project_id integer, ts timestamp, event_type integer )
>
> I need an aggregated list of worktime per user, per project, per day.
>
> The users can switch projects during the day so I can't work this out with
> min(ts) and max(ts).
>
> Is there a clever way to get this with SQL ?
>
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