Hi Jörg,
> How can I outsource a subquery?
maybe you could try to use "Common Table Expressions" and do something like:
WITH foerd_id AS (SELECT foerd_id FROM foerds WHERE mass_id = '55896')
SELECT DISTINCT a.*,
( SELECT SUM(std) FROM all_std WHERE (a.status <=5 AND status = 5) AND foerd_id IN (SELECT *
FROMfoerd_id)
) AS done_std,
( SELECT SUM(anerk_std) FROM all_std WHERE (a.status >5 AND status < 5) AND foerd_id IN
(SELECT* FROM foerd_id)
) AS accepted_std
FROM table_a a
WHERE a.mass_id = '55896’;
or with some more “outsourcing”:
WITH all_std_foerds AS (SELECT * FROM all_std WHERE foerd_id IN (SELECT foerd_id FROM foerds WHERE
mass_id= '55896') AND status <= 5)
SELECT DISTINCT a.*,
( SELECT SUM(std) FROM all_std_foerds WHERE (a.status <=5 AND status = 5)
) AS done_std,
( SELECT SUM(anerk_std) FROM all_std_foerds WHERE (a.status >5 AND status < 5)
) AS accepted_std
FROM table_a a
WHERE a.mass_id = '55896';
Or maybe unnesting both aggregate subqueries in order to merge them and make use of FILTER-clauses
(https://www.postgresql.org/docs/9.5/static/sql-expressions.html#SYNTAX-AGGREGATES)might be a nice option. Something
like:
SELECT DISTINCT a.*, SUM(std) FILTER (WHERE a.status <=5 AND s.status = 5) AS done_std,
SUM(anerk_std)FILTER (WHERE a.status >5 AND s.status < 5) AS accepted_std
FROM table_a a, all_std s
WHERE a.mass_id = '55896' AND s.status<=5 AND s.foerd_id IN (SELECT foerd_id FROM foerds WHERE mass_id = '55896')
GROUP BY a.mass_id, a.status;
Regards, Benjamin
