On 02.10.2011 08:31, Nikhil Sontakke wrote:
> Consider the following sequence of commands in a psql session:
>
> postgres=#create table public.sample(x int);
> postgres=#create schema new;
> postgres=#create table new.sample(x int);
> postgres=#set search_path=public,new;
>
> postgres=#\dt
> Schema | Name | Type | Owner
> -------------------------------------------
> public | sample | table | postgres
> (1 row)
>
> We should have seen two entries in the above listing. So looks like a bug to
> me.
No, that's the way it's designed to work. It shows the objects that are
visible to you, without schema-qualifying them. See
http://www.postgresql.org/docs/9.0/interactive/app-psql.html#APP-PSQL-PATTERNS
:
> Whenever the pattern parameter is omitted completely, the \d commands display all objects that are visible in the
currentschema search path — this is equivalent to using * as the pattern. (An object is said to be visible if its
containingschema is in the search path and no object of the same kind and name appears earlier in the search path. This
isequivalent to the statement that the object can be referenced by name without explicit schema qualification.) To see
allobjects in the database regardless of visibility, use *.* as the pattern.
-- Heikki Linnakangas EnterpriseDB http://www.enterprisedb.com
