Thanks.
On 19/06/2011 8:09 AM, David Johnston wrote:
> An alternative approach would be to select using a IN condition on the where clause and group by column 1 and column
2. Then, using this as a sub-select group by the resultant column 1 and a count on column two. The matching
identifiersare those with a count equal to the number of entries in the original IN condition.
>
> Basically count how many of values each distinct key in column 1 matches and keep those keys where the count and the
numberof values match.
>
> David J.
>
>
> On Jun 18, 2011, at 17:51, Daron Ryan<daron.ryan@gmail.com> wrote:
>
>> Hello,
>>
>> I need to search a table to find sets of rows that have a column matching itself for the whole set and another
columnmatching row for row with a list I am going to supply. The result I should receive should be value of the column
thatmatches itself.
>>
>> For example given the following data in my table:
>>
>> 3; 1
>> 3; 2
>> 4; 8
>> 4; 9
>> 4; 10
>>
>> I might need to search for 1,2. This should produce the result 3. Or if I were to search for 8, 9, 10 the result
shouldbe 4. Searching for 8, 9 should produce an empty result as should 8, 9, 10, 11.
>>
>> Can anyone recommend a strategy?
>>
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