Am 16.08.2010 14:45, schrieb Matthew Wilson:
> I'm converting some procedural code to SQL as an experiment. Here's the
> pseudocode:
>
> c = a - b
> if c< 0 then d = 'no'
> else d = 'yes'
>
> In SQL, I've got this:
>
> select a, b, a - b as c,
> case when a - b< 0 then 'no'
> else 'yes'
> end as d
>
> from foo;
>
> This is a trivial example, but you can see how I calculate a - b two
> separate times.
>
> In reality, I have much nastier calculations and they happen more than
> just twice.
>
> I'm looking for an elegant solution for this puzzle. I don't want to
> repeat that a - b part over and over because I likely will need to
> change how c gets defined and I don't want to have to change more than
> one place in the code.
>
> All I can come up with so far is to use a view and then another view on
> top of that one:
>
> create view v1 as
> select a, b, a - b as c
> from foo;
>
> create view v2 as
> select a, b, c,
> case when c< 0 then 'no'
> else 'yes'
> end as d
> from v1;
>
> This is better than the first solution because c is only defined in a
> single place. Is this the best possible solution?
>
> Thanks for the help.
>
> Matt
>
>
>
You can also use the ' with Queries ' option to solve this Problem like
this:
with table_1 as (select a,b, a-b as c from foo)
Select a,b, c,
case when c<0 then 'no'
else 'yes' end as d
from table_1;
I hope , it will help you
--
Eric Ndengang
Junior Datenbankentwickler
Affinitas GmbH | Kohlfurter Straße 41/43 | 10999 Berlin | Germany
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