antony baxter wrote:
> // Retrieve that Locale's ID by its Data:
> p = c.prepareStatement("SELECT COUNT(*) FROM testing WHERE variant = ?");
To avoid conditionally rewriting your query to use IS NULL / IS NOT NULL
instead of equality, you could also use IS DISTINCT FROM. Instead of:
where variant = ?
try using:
where not (variant is distinct from ?)
craig=# \pset null '<null>'
Null display is "<null>".
craig=# select null = null;
?column?
----------
<null>
(1 row)
craig=# select not( null is distinct from null );
?column?
----------
t
(1 row)
craig=# select not (1 is distinct from 1);
?column?
----------
t
(1 row)
craig=# select not (1 is distinct from 2);
?column?
----------
f
(1 row)
craig=# select not (null is distinct from 2);
?column?
----------
f
(1 row)
See:
http://www.postgresql.org/docs/8.3/static/functions-comparison.html
--
Craig Ringer
