Axel Rau wrote:
>
> Am 29.09.2005 um 10:30 schrieb Richard Huxton:
>
>> Axel Rau wrote:
>>
>>> SELECT T2.T2_name, COUNT(T1.id) AS xx
>>> FROM T2, T1
>>> WHERE T2.id = T1.fk_t2
>>> GROUP BY T2.T2_name
>>> HAVING COUNT(T1.id) > 1
>>> ORDER BY xx DESC;
>>> t2_name | xx
>>> ---------+----
>>> T2-N2 | 3
>>> T2-N3 | 2
>>> (2 rows)
>>> Adding column t1_name to the result set breaks COUNT(T1.id):
>>> SELECT T2.T2_name, T1.T1_name, COUNT(T1.id) AS xx
>>> FROM T2, T1
>>> WHERE T2.id = T1.fk_t2
>>> GROUP BY T2.T2_name, T1.T1_name
>>> HAVING COUNT(T1.id) > 1
>>> ORDER BY xx DESC;
>>> t2_name | t1_name | xx
>>> ---------+---------+----
>>> (0 rows)
>>> How can I do this with pg ?
>>
>>
>> Do what? You don't say what results you are expecting.
>>
>> Do you want:
>> 1. ALL values of T1_name (in which case what count do you want)?
>> 2. The FIRST value of T1_name (in which case what do you mean by first)?
>
>
> #1.:
>
> t2_name | t1_name | count
> ---------+---------+-------
> T2-N2 | T1-CCC | 3
> T2-N3 | T1-FFF | 2
> T2-N2 | T1-BBB | 3
> T2-N2 | T1-DDD | 3
> T2-N3 | T1-EEE | 2
Ah - this is two questions:
1. What are the unique (t2_name,t1_name) pairings?
2. How many different (t1.id) values are there for each t2.
So - something like:
SELECT names.T2_name, names.T1_name, counts.num_t2
FROM
(
SELECT DISTINCT T2.T2_name, T1.T1_name
FROM T2,T1
WHERE T2.id = T1.fk_t2
) AS names,
(
SELECT T2.T2_name, COUNT(T1.id) AS num_t2
FROM T2, T1
WHERE T2.id = T1.fk_t2
GROUP BY T2.T2_name
HAVING COUNT(T1.id) > 1
) AS counts
WHERE names.T2_name = counts.T2_name
;
You could write the "names" sub-query with a GROUP BY if you wanted of
course.
-- Richard Huxton Archonet Ltd
