let ff your table...<br /> try this:<br /><b>select </b><br /> a.id, <br /> a.date, <br /> a.hours, <br />
(<b>select </b>sum(b.hours) <br /> <b>from </b>ff as b<br /> <b>where </b>a.id = b.id <br />
<b>group</b>by b.id <br /> ) as a <br /> <b>from </b>ff as a;<br /><br /> bye,<br /> Luca<br /><br /> Henry
Ortegaha scritto:<br /><blockquote cite="mid2bffcc33050805092862a01b93@mail.gmail.com" type="cite"><pre wrap="">I have
theff data:
id | date | hours
AAA 07-01-2005 3
AAA 07-02-2005 4
BBB 07-01-2005 6
BBB 07-02-2005 2
BBB 07-03-2005 7
Would it be possible to get the ff:
id | date | hours | id_total
AAA 07-01-2005 3 7
AAA 07-02-2005 4 7
BBB 07-01-2005 6 15
BBB 07-02-2005 2 15
BBB 07-03-2005 7 15
So it's like SUM OF, but not Grouped By? Is this possible at all?
Thank you for any help.
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