Try:
Order by mod( id_mois + 12 - <current_month>, 12)
frederic massot wrote:
>
> Hello,
>
> I have a table containing the months of the year :
>
> travail=> select * from mois order by id_mois;
>
> id_mois|mois_fr |mois_en |mois_de
> -------+---------+---------+---------
> 1|Janvier |January |Januar
> 2|Fevrier |February |Februar
> 3|Mars |March |Marz
> 4|Avril |April |April
> 5|Mai |May |Aber
> 6|Juin |June |Juni
> 7|Juillet |July |Juli
> 8|Aout |August |August
> 9|Septembre|September|September
> 10|Octobre |October |Oktober
> 11|Novembre |November |November
> 12|Decembre |December |Dezember
> (12 rows)
>
> And I try to obtain for one month given (for example August : 8) two
> previous months, the current month, and nine next months :
>
> id_mois|mois_fr |mois_en |mois_de
> -------+---------+---------+---------
> 6|Juin |June |Juni
> 7|Juillet |July |Juli
> 8|Aout |August |August
> 9|Septembre|September|September
> 10|Octobre |October |Oktober
> 11|Novembre |November |November
> 12|Decembre |December |Dezember
> 1|Janvier |January |Januar
> 2|Fevrier |February |Februar
> 3|Mars |March |Marz
> 4|Avril |April |April
> 5|Mai |May |Aber
>
> Do you see how making in a SQL request ?
>
> Thank you.
> --
> ==============================================
> | FREDERIC MASSOT |
> | http://www.juliana-multimedia.com |
> | mailto:frederic@juliana-multimedia.com |
> ===========================Debian=GNU/Linux===
>
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