> Bruce Momjian wrote:
> >
> > I have been thinking about how to simulate an outer join. It seems the
> > best way is to do:
> >
> > SELECT tab1.col1, tab2.col3
> > FROM tab1, tab2
> > WHERE tab1.col1 = tab2.col2
> > UNION ALL
> > SELECT tab1.col1, NULL
> > FROM tab1
> > WHERE tab1.col1 NOT IN (SELECT tab2.col2 FROM tab2)
> >
> > Comments? I know someone was asking about this recently.
Mike Mascari wrote:
>
> I wouldn't use IN ;-)
>
> SELECT table1.key, table2.value
> FROM table1, table2
> WHERE table1.key = table2.key
> UNION ALL
> SELECT table1.key, NULL
> FROM table1 WHERE NOT EXISTS
> (SELECT table2.key FROM table2 WHERE table1.key = table2.key);
FWIW, that's exactly Joe Celko's SQL-89 workaround for OUTER JOINs in 'SQL for
Smarties'. Well in fact he uses (SELECT * FROM table2 WHERE table1.key =
table2.key) as the subquery, but I presume that's an insignificant difference.
Julian Scarfe
