Robert Haas <robertmhaas@gmail.com> writes:
> On Mon, Dec 6, 2021 at 4:05 PM Tom Lane <tgl@sss.pgh.pa.us> wrote:
>> select f(t) from t(x,y);
>>
>> If we adopt the "rename for all purposes" interpretation, then
>> the second SELECT must fail, because what f() is being passed is
>> no longer of type t.
> For me, the second SELECT does fail:
> rhaas=# select f(t) from t(x,y);
> ERROR: column "x" does not exist
Ah, sorry, I fat-fingered the alias syntax. Here's a tested example:
regression=# create table t (a int, b int);
CREATE TABLE
regression=# insert into t values(11,12);
INSERT 0 1
regression=# create function f(t) returns int as 'select $1.a' language sql;
CREATE FUNCTION
regression=# select f(t) from t as t(x,y);
f
----
11
(1 row)
If we consider that the alias renames the columns "for all purposes",
how is it okay for f() to select the "a" column?
Another way to phrase the issue is that the column names seen
by f() are currently different from those seen by row_to_json():
regression=# select row_to_json(t) from t as t(x,y);
row_to_json
-----------------
{"x":11,"y":12}
(1 row)
and that seems hard to justify.
regards, tom lane
