Re: unique, partitioned index fails to distinguish index key fromINCLUDEd columns - Mailing list pgsql-hackers

From Justin Pryzby
Subject Re: unique, partitioned index fails to distinguish index key fromINCLUDEd columns
Date
Msg-id 20190115023022.GJ15177@telsasoft.com
Whole thread Raw
In response to Re: unique, partitioned index fails to distinguish index key fromINCLUDEd columns  (Alvaro Herrera <alvherre@2ndquadrant.com>)
Responses Re: unique, partitioned index fails to distinguish index key fromINCLUDEd columns  (Alvaro Herrera <alvherre@2ndquadrant.com>)
List pgsql-hackers
On Mon, Jan 14, 2019 at 07:31:07PM -0300, Alvaro Herrera wrote:
> On 2019-Jan-09, Justin Pryzby wrote:
> 
> > -- Fails to error
> > postgres=# CREATE UNIQUE INDEX ON t(j) INCLUDE(i);
> > 
> > -- Fail to enforce uniqueness across partitions due to failure to enforce inclusion of partition key in index KEY
> > postgres=# INSERT INTO t VALUES(1,1);
> > postgres=# INSERT INTO t VALUES(2,1); 
> 
> Doh.  Fix pushed.  Commit 8224de4f42cc should have changed one
> appearance of ii_NumIndexAttrs to ii_NumIndexKeyAttrs, but because of
> the nature of concurrent development, nobody noticed.

I figured as much - I thought to test this while trying to fall asleep,
without knowing they were developed in parallel.

Should backpatch to v11 ?
0ad41cf537ea5f076273fcffa4c83a184bd9910f

Thanks,
Justin


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