am Thu, dem 21.06.2007, um 11:10:02 +0200 mailte Dani Castaños folgendes:
> Hi!
>
> I'm trying to build a query to get if there is an occurrence for a field
> for each alphabetical letter.
> My first thought to know it was to do something like:
>
> SELECT COUNT(field) FROM table WHERE UPPER( field ) LIKE UPPER( 'A%' )
> LIMIT 1;
> SELECT COUNT(field) FROM table WHERE UPPER( field ) LIKE UPPER( 'B%' )
> LIMIT 1;
> SELECT COUNT(field) FROM table WHERE UPPER( field ) LIKE UPPER( 'C%' )
> LIMIT 1;
> ...
> and so on...
>
> Is there any way to do it in only one query??
I'm not sure if i understand you correctly, sorry, if not.
test=*# select * from w; t
--------testfoobarfoobar
(4 rows)
test=*# select chr(x), count(1) from generate_series(65,90) x, w where
upper(substring (w.t from 1 for 1)) ~ chr(x) group by 1;chr | count
-----+-------T | 1B | 1F | 2
(3 rows)
Andreas
--
Andreas Kretschmer
Kontakt: Heynitz: 035242/47150, D1: 0160/7141639 (mehr: -> Header)
GnuPG-ID: 0x3FFF606C, privat 0x7F4584DA http://wwwkeys.de.pgp.net
