Peter Kovacs escribió:
> But if an individual disk fails in a disk array, sooner than later you
> would want to purchase a new fitting disk, walk/drive to the location
> of the disk array, replace the broken disk in the array and activate
> the new disk. Is this correct?
Ideally you would have a spare disk to let the array controller replace
the broken one as soon as it breaks, but yeah, that would be more or
less the procedure. There is a way to defer the walk/drive until a more
convenient opportunity presents.
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Alvaro Herrera http://www.CommandPrompt.com/
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