Re: SELECT substring with regex - Mailing list pgsql-sql

From Jim Buttafuoco
Subject Re: SELECT substring with regex
Date
Msg-id 20060707203420.M77919@contactbda.com
Whole thread Raw
In response to Re: SELECT substring with regex  (T E Schmitz <mailreg@numerixtechnology.de>)
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---------- Original Message -----------
From: T E Schmitz <mailreg@numerixtechnology.de>
To: pgsql-sql@postgresql.org
Sent: Fri, 07 Jul 2006 20:23:50 +0100
Subject: Re: [SQL] SELECT substring with regex

> Rodrigo De Leon wrote:
> > On 7/7/06, T E Schmitz <mailreg@numerixtechnology.de> wrote:
> > 
> >> But that takes me to the next problem:
> >>
> >> For the sake of the example I simplified the regular pattern.
> >> In reality, BASE_NAME might be:
> >>
> >> 28mm
> >> 28-70mm
> >>
> >> So the reg. expr. requires brackets:
> >>
> >> substring (NAME, '^(\\d+(-\\d+)?mm)' ) as BASE_NAME
> >>
> >> Actually, the pattern is more complex than that and I cannot see how I
> >> can express it without brackets.
> > 
> > 
> > Maybe:
> > 
> > select
> > substring ('28-70mm LD AD Asp XR Macro', '^[\\d-]*mm' ) as BASE_NAME
> 
> Sorry, but that would also capture something like
> 10-30-59mm
> 
> The pattern describes either a single length (120 millimeters) or a 
> range (30 to 70 millimetres), hence:
> 
> \\d+(-\\d+)?mm
> 
> The ? quantifier refers to the combination of '-' and digits and has to 
> be bracketed.
> 
> If the brackets cannot be avoided in the expression, your original 
> suggestion might come in handy though:
> 
> SELECT
> substring (NAME, '^\\d+(-\\d+)?mm') AS BASE_NAME ,
> substr(
>      NAME
>      , char_length(
>          substring (NAME, '^\\d+(-\\d+)?mm')
>      ) + 2
> ) AS SUFFIX
> 
> Still, I'd be interested to know whether there is a 'more elegant' solution.
> 
> --
> 
> Regards,
> 
> Tarlika Elisabeth Schmitz
> 
> ---------------------------(end of broadcast)---------------------------
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> 
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------- End of Original Message -------



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